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27-06-2017
Mathematics

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(16x^2 - 25) ÷ (4x + 5)
DO NOT INCLUDE PARENTHESES IN YOUR ANSWER

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Banabanana Banabanana

27-06-2017

[tex] \cfrac{16x^2-25}{4x+5}= \cfrac{(4x)^2-5^2}{4x+5}= \cfrac{(4x-5)(4x+5)}{(4x+5)}= 4x-5[/tex]

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