Answer: [tex]\frac{sinA}{3.2}=\frac{sin110^{\circ}}{4.6}[/tex]
[tex]\text{or }sinA=3.2 \times\frac{sin110^{\circ}}{4.6}[/tex]
Step-by-step explanation:
By the sin law,
If a, b and c are the sides of a triangle ABC,
Then by the sine law,
[tex]\frac{sinA}{a} = \frac{sin B}{b}=\frac{sinC}{c}[/tex]
According to the question,
AB = 4.6 meter,
AX = 2.4 meter,
BX = 3.2 meter,
m∠AXB = 110°
Hence, by the sine law,
[tex]\frac{sinA}{3.2}=\frac{sin110^{\circ}}{4.6}[/tex]
[tex]sinA=3.2 \times\frac{sin110^{\circ}}{4.6}[/tex]
Which is the required equation for finding the angle A.
