What is the value of s in the equation 3r = 10 + 5s, when r = 10?

To answer the question above, we need to know the rules of arithmetic operations in algebra. The same variable only can be operated with the same variable for example, if 2x + 3x then the result is 5x, but 2x + 3y cannot be 5xy because the variable is different. To answer the question we need to know the value of r and s. Now, check the question, what is the result of the equation 3r = 10 + 5s, when r = 10?.

To find out the value of s, the value of r is known so we just include it to the equation.

r = 10 then 3r = 3 . (10) = 30

3r = 10 + 5s

30 = 10 + 5s

(because there are 2 Constanta and 1 variable, we must change the place and the value of 1 Constanta to operate them)

30 = 10 + 5s

30 - 10 = 5s

(10 changed to -10 because it moves to the other side of the equal sign)

20 = 5s

(to find out the value of s or a variable, we need to divide Constanta with coeffitient in remaining)

20/5 = s

4 = s, so the value of s is 4

now we finish the first equation which is 3r = 10 + 5s, we just include the value of the variable then finish it.

3r = 10 + 5s

3 . (10) = 10 + 5 . (4)

30 = 10 + 20

30 = 30

because they have the same result, it means the value of variables was right. so the final result of the question is 30.