Answer:
Option a is correct
(f∘g)(10)=37
Step-by-step explanation:
Given the functions:
[tex]f(x) = x^2 + 1[/tex]
[tex]g(x) =x-4[/tex]
We have to find (f∘q)(10).
At x = 10
g(10) = 10-4 = 6
then;
[tex](f o g)(10) = f(g(10))[/tex]
Substitute the value of g(10) we have;
[tex](f o g)(10) = f(6)[/tex]
Substitute the value of x = 6 in f(x) we have;
[tex](f o g)(10) =6^2+1[/tex]
⇒[tex](f o g)(10) =36+1=37[/tex]
Therefore, the value of (f∘g)(10) is, 37