Basically, we need to isolate y
Assuming 0 is unnecessary:
x + 19y = 38
19y = -x + 38
[tex]y= \frac{-x+38}{19} [/tex]
[tex]y= -\frac{x}{19} + \frac{38}{19} [/tex]
[tex]y= -\frac{x}{19} +2[/tex]
Assuming that 0 is necessary:
0x+19y = 38
0•x is equivalent to 0 so that cancels out x leaving us with
19y = 38
y = 38/19
y = 2
If the 0 is necessary, your answer is y = 2.
If the 0 is unnecessary, your answer is y = -(x/19)+2
