Respuesta :
Answer:
Step-by-step explanation:
Given is a differential equation as:
[tex]y'=4x\sqrt{1-y^2}[/tex]
We can solve this by separation of variables method
[tex]\frac{dy}{\sqrt{1-y^2} } =4xdx\\sin^{-1} y = 2x^2+C[/tex]
To find C:
Given y(0) =4
Substitute x=0 and y =4
sin inverse of 4 = C
But sin inverse is valid only for values between -1 and 1
Hence C is not a real value
No solution for this.