k, so
vertex i (-5,-2)
neat
vertex form
y=a(x-h)²+k
vertex is (h,k)
a is the coefieint of the squred term in the parbola's equestion
so
given vertex of (-5,-2)
y=a(x-(-5))²+(-2)
y=a(x+5)²-2
a point si (-4,2)
sub that point
2=a(-4+5)²-2
2=a(1)²-2
2=a-2
add 2
4=a
the value of the coefieint of the squred expression part is 4
