Respuesta :
[tex]\bf -2(x-3)^3(x-3)^2(x+1)=0\impliedby x-intercepts
\\\\\\
x=
\begin{cases}
3\\
-1
\end{cases}[/tex]
now, the (x-3) is there 5 times, namely (x-3)(x-3)(x-3) and (x-3)(x-3), that simply means, the root of 3 has a multiplicity of 5, is all
to get the y-intercepts, simple, when the graph touches the y-axis, "x" is zero, thus [tex]\bf -2(0-3)^3(0-3)^2(0+1)=y\impliedby y-intercepts \\\\\\ -2(-3)^3(-3)^2(1)=y\implies -2(-27)(9)(1)=y\implies 486=y[/tex]
now, the (x-3) is there 5 times, namely (x-3)(x-3)(x-3) and (x-3)(x-3), that simply means, the root of 3 has a multiplicity of 5, is all
to get the y-intercepts, simple, when the graph touches the y-axis, "x" is zero, thus [tex]\bf -2(0-3)^3(0-3)^2(0+1)=y\impliedby y-intercepts \\\\\\ -2(-3)^3(-3)^2(1)=y\implies -2(-27)(9)(1)=y\implies 486=y[/tex]
