[tex]\bf \begin{array}{ccllll}
in^3&\$\\
\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\\
785&9.99\\
1&x
\end{array}\implies \cfrac{785}{1}=\cfrac{9.99}{x}[/tex]
solve for "x"
