Respuesta :
In the interval ([0, 2pi]), (cos(theta)) is maximum when (theta = 0, 2pi). Therefore, (cos(2x - pi)) is maximum when (2x - pi = 0, 2pi) or
(x = pi/2, x= 3pi/2)
(x = pi/2, x= 3pi/2)
Answer:
x=pi over 2; x=3 pi over 2
Step-by-step explanation:
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