Respuesta :
 CO is the limiting reactantÂ
( 25.0 x 3 = 75 moles of CO are required)Â
Moles Fe = 30.0 x 2 / 3 = 20.0Â
mass Fe = 20.0 x 55.847 g/mol=1117 gÂ
I'm just saying
( 25.0 x 3 = 75 moles of CO are required)Â
Moles Fe = 30.0 x 2 / 3 = 20.0Â
mass Fe = 20.0 x 55.847 g/mol=1117 gÂ
I'm just saying
When 13 moles of hematite react with 38 moles of carbon monoxide, 1,412.7 grams of iron is produced.
How we calculate mass from moles?
Mass of any substance can be calculated by using its moles as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction :
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(s)
From the stoichiometry of the solution, it is clear that:
1 mole of Fe₂O₃ = react with 3 moles of CO
13 moles of Fe₂O₃ = react with 13×3=39 moles of CO
Given moles of CO = 38 moles which is 1 mole less than the calculated moles.
So, CO is the limiting reagent, it means it totally coverts into product.
3 moles of CO = produce 2 moles of Fe
38 moles of CO = produce 2/3×38= 25.3 moles of Fe
Now we convert this moles of Fe into grams by using the above equation, where molar mass of Fe is 55.84 g/mol.
W = n×M, where
W = 25.3 × 55.84 = 1,412.7 grams
Hence, 1,412.7 grams is the mass of iron.
To know more about moles, visit the below link:
https://brainly.com/question/1464305