At 5:45 p.m., a jet is located 108 mi due east of a city. A second jet is located 214 mi due north of the city. To the nearest tenth of a mile, what is the distance between the two jets? Enter your answer as a decimal in the box.
By connecting the distances traveled by the jet and the distance between them, we form a right triangle with hypotenuse equal to the unknown distance. Using the Pythagorean, h² = a² + b² Substituting, h² = (108 mi)² + (214 mi)² h = 239.71 miles Thus, the distance between them is approximately 239.71 miles.
