Respuesta :

[tex]x;\ x+1;\ x+2;\ x+3-four\ consecutive\ whole\ numbers\\\\(x)+(x+1)+(x+2)+(x+3)=54\\4x+6=54\ \ \ \ |subtract\ 6\ from\ both\ sides\\4x=48\ \ \ \ |divide\ both\ sides\ by\ 4\\x=12\\\\the\ four\ number:x+3=12+3=\boxed{15}[/tex]

Otras preguntas