Answer:
[tex](13y^2+3y-5)[/tex]
Step-by-step explanation:
We have been given an expression [tex]91y^3+21y^2-35y[/tex] when divided by [tex]7y[/tex]
Here, we have numerator [tex]91y^3+21y^2-35y[/tex] and denominator is [tex]7y[/tex]
Taking out the common terms from numerator which is [tex]7y[/tex] we will get [tex]7y(13y^2+3y-5)[/tex]
Now, cancel out the common terms from numerator and denominator which is [tex]7y[/tex] we will get
[tex](13y^2+3y-5)[/tex]
Therefore the required quotient is [tex](13y^2+3y-5)[/tex].
