PLEASE HELP ME
In the following reaction, what element is made?

Answer: [tex]^{244}_{97}\textrm {Bk}[/tex]
Explanation:
A nuclear fission reaction is defined as the reaction in which a heavy nucleus splits into small nuclei along with release of energy.
The given reaction is:
[tex]^{241}_{95}\textrm{Am}+^{4}_{2}\textrm{He}\rightarrow ^{A}_{Z}\textrm {}+^{1}_{0}n[/tex]
To calculate A:
Total mass on reactant side = total mass on product side
[tex]241+4=A+1[/tex]
[tex]A=244[/tex]
To calculate Z:
Total atomic number on reactant side = total atomic number on product side
95 + 2 = Z + 0
Z = 97
Thus the element will be berkelium with atomic number of 97 and element will be represented as [tex]^{244}_{97}\textrm {Bk}[/tex]