The chemical reaction would be:
HBr + LiOH = LiBr + H2O
We are given the concentration of the other reactant. We use these given values and the reaction to relate to moles of HBr needed. We do as follows:
0.253 mol / L ( .005 L) ( 1 mol HBr / 1 mol LiOH ) = 0.0013 mol HBr
Molarity = 0.0013 / 0.01 = 0.13 M
