contestada

Which equation choice could represent the graph shown below?
1) F(x) = (x - 4)(x + 1)(x - 6)
2) F(x) = (x - 4)(x - 1)(x - 6)
3) F(x) = (x - 4)(x - 1)(x + 6)
4) F (x) = (x + 4(x - 1)(x - 6)

Which equation choice could represent the graph shown below 1 Fx x 4x 1x 6 2 Fx x 4x 1x 6 3 Fx x 4x 1x 6 4 F x x 4x 1x 6 class=

Respuesta :

xero099

The algebraic equation of the cubic function set on Cartesian plane is f(x) = (x + 6) · (x - 1) · (x - 4). (Correct choice: 3)

What equation does represent a cubic function?

In this problem we find the representation of a cubic function set on Cartesian plane, whose definition as algebraic equation is shown below:

f(x) = a · (x - r₁) · (x - r₂) · (x - r₃)

Where:

  • a - Lead coefficient.
  • r₁, r₂, r₃ - Roots of the polynomial.

Graphically speaking, the roots of the polynomials are the points of the curve on x-axis. If we know that a = 1, r₁ = - 6, r₂ = 1 and r₃ = 4, then the algebraic equation of the cubic function is:

f(x) = (x + 6) · (x - 1) · (x - 4)

To learn more on cubic equations: https://brainly.com/question/13730904

#SPJ1

semsee45

Answer:

3)  f(x) = (x - 4)(x - 1)(x + 6)

Step-by-step explanation:

The x-intercepts of a function are the points at which the curve crosses the x-axis, so when f(x) = 0.

From inspection of the given graph, the curve crosses the x-axis at:

  • x = -6
  • x = 1
  • x = 4

According to the Factor Theorem, if f(x) is a polynomial and f(a) = 0, then (x - a) is a factor of f(x).

Therefore, as f(x) = 0 when x = -6, x = 1 and x = 4, then (x + 6) and (x - 1) and (x - 4) are factors of the polynomial.

Therefore, the equation of the function is:

  • f(x) = (x - 4)(x - 1)(x + 6)