Respuesta :

irspow
That is a geometric sequence of the form a(n)=-3(1/2)^(n-1)

The sum of any geometric sequence is:

s(n)=a(1-r^n)/(1-r)

and if r^2<1 it converges to a sum of:

s=a/(1-r).... in this case:

s=-3/(1-1/2)

s=-3/(1/2)

s=-6
naratnight

Answer:

D, -6

Step-by-step explanation:

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