Answer:
13. a
14. c
15. b
16. c
17. d
Step-by-step explanation:
You want various probabilities associated with selections from the given Venn diagram.
Probability
Assuming a student is chosen at random, the probability they will play any sport shown in the diagram is the fraction of students in that section of the diagram. There are a total of 66 students represented in the diagram (the sum of the individual numbers). So, for example, the probability that a student plays only Basketball is 10/66, as 10 is the number in the Basketball section that is not also in some other section.
MC13
"Football or baseball" includes every section of the diagram except "basketball only". Hence the fraction is (66 -10)/66 = 56/66 = 28/33.
The probability a randomly selected student plays football or baseball is 28/33.
MC14
The numbers in where the "football" circle overlaps the "baseball" circle are 3 and 5. The fraction of students playing both is (3+5)/66 = 4/33.
MC15
The sum of all of the numbers in the "football" circle is ...
26 +6 +5 +3 = 40
The probability the student plays football is 40/66 = 20/33.
MC16
The number in the "football" circle that is not in any other circle is 26.
The probability the student only plays football is 26/66 = 13/33.
MC17
The numbers in the "baseball" circle that are not in the "football" circle are 7 and 9. The fraction playing baseball, but not football, is (7+9)/66 = 8/33.
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