Respuesta :
a) Let x = number of presale tickets
y = number of day of show tickets
x + y =< 800
6x + 9y >= 5000
b) 6x + 9y >=5000
6(440) + 9y >=5000
y >= 262.2
263 tickets
440 advance purchase tickets added to 263 day of show tickets is 703 tickets, which is below the 800 ticket maximum.
y = number of day of show tickets
x + y =< 800
6x + 9y >= 5000
b) 6x + 9y >=5000
6(440) + 9y >=5000
y >= 262.2
263 tickets
440 advance purchase tickets added to 263 day of show tickets is 703 tickets, which is below the 800 ticket maximum.