Respuesta :
Height over shadow
H/S
9 in is 9/12=.75
So
Boys height /shadow. Flags height /shadow
4.75/6= X/19
Cross multiply
6x= 90.25
Divide by 6
X= 15.0
H/S
9 in is 9/12=.75
So
Boys height /shadow. Flags height /shadow
4.75/6= X/19
Cross multiply
6x= 90.25
Divide by 6
X= 15.0
Answer:
The height of the flagpole(to the nearest tenth) is, 15.0 ft
Step-by-step explanation:
Proportion states that the two ratios or fractions are equal
As per the statement: If the boy is 4' 9" tall and his shadow is 6 ft. and shadow of the flagpole is 19 ft.
let the height of the flagpole be, h.
Use conversion:
1 ft = 12 inches.
Given: Height of the boy = [tex]4'9" =4\frac{9}{12} = 4\frac{3}{4} = \frac{19}{4} ft[/tex] , Shadow of the boy = 6 ft. and shadow of the flagpole=19 ft.
Using definition of proportion;
[tex]\frac{Height of the boy}{Shadow of the boy} =\frac{Height of flagpole}{Shadow of flagpole}[/tex]
[tex]\frac{\frac{19}{4}}{6}= \frac{h}{19}[/tex]
By cross multiply;
[tex]\frac{19}{4} \times 19 =6h[/tex]
[tex]\frac{361}{4} = 6h[/tex]
Divide both sides by 6 we get;
[tex]\frac{361}{24} = h[/tex]
⇒ h = 15.0416667 ft.
therefore, the height of the flagpole(to the nearest tenth) is, 15.0 ft
