A pen rolls off a 0.55–meter high table with an initial horizontal velocity of 1.2 meters/second. At what horizontal distance from the base of the table will the pen land?
we are asked in the problem to determine the horizontal distance achieved by rolling of a pen from a vertical distance of 0.55 m at 1.2 m/s. we use the formula in this case,
t = √[2y/g] where g is the gravitational acceleration t = √[2*0.55/9.8] =0.335 s
