Respuesta :

[tex]\bf sin^{-1}(6x)\\\\ -----------------------------\\\\ \textit{using the chain-rule}\implies \cfrac{d}{dx}\left[ sin^{-1}(6x) \right]\implies \cfrac{1}{\sqrt{1-(6x)^2}}\cdot 6\\\\ \cfrac{6}{\sqrt{1-36x^2}}[/tex]