Circumference of the smaller circle, using [tex]C = \pi d[/tex], is approximately equal to 18.85 (I used the high floating point precision approximation of pi my calculator has in memory, then rounded to 2 decimal points.)
Using the formula [tex]S = 0.2L[/tex], which in English says "the smaller circle's circumference is equal to 20% of the larger circle's", we can substitute the known value S: [tex]18.85 = 0.2L[/tex] and solve for L: [tex] \frac{18.5}{0.2} = L, L = 92.5[/tex].
So the larger circle has a circumference approximately equal to 92.5 units.
