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What is the magnitude of the electric field 23.4 cm directly above an isolated 3.50×10−5 C charge?

Respuesta :

scme1702
The strength of the electric field can be found using:
E = kQ/d²
E = 9 x 10⁹ x 3.5 x 10⁻⁵ / (0.234)²
E = 5.75 x 10⁶ N/C

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