The volume of argon will be 10.57 L.
Apply the ideal gas law, PV = nRT, where n is the number of moles and R is the gas constant.
We must divide the given mass of argon by its molar mass because we have mass and need moles. Argon has a molar mass of 40 g/mol.
So the number of moles of Argon in 15.2g is = [tex]\frac{15.2}{40} = 0.38[/tex]mol
Given:
P = 1.04 atm
n = 0.38 mol
R = [tex]0.082057 Latm K^{-1} mol^{-1}[/tex]
T = 353 K
Unknown:
V
Solution:
V = [tex]\frac{nRT}{P}[/tex]
V = [tex]\frac{0.38*0.082*353}{1.04} = 10.57[/tex] L
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