Yes, if Trapezoid abcd has vertices a(2, 4), b(5, 4), c(7, 1), and d(0, 1) , ABCD is an isosceles trapezoid.
Since, If in a trapezoid two opposite nonparallel sides are equal then it is called isosceles trapezoid.
In trapezoid ABCD sides are AB, BC, CD and DA.
According to the question, A≡(2,4) B≡(5,4) C≡(7,1) and D≡(0,1)
After making the diagram of ABCD, we found that DA and BC are nonparallel sides.
And, by the distance formula BC = √((7 - 5)² + (1 - 4)²) =
⇒ BC =√(4 + 9)
⇒BC = √13 unit.
Similarly, DA = √((0 - 2)² + (1 - 4)²)
DA = √(4 + 9)
⇒ DA = √13 unit.
Thus, In trapezoid ABCD, two non parallel sides BC and DA are equal.
Therefore, trapezoid ABCD is a isosceles trapezoid.
To learn more about distance formula refer here
https://brainly.com/question/7243416
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