The force exerted by each wire on the other is 2.646N and it is away from each other.
The distance between the parallel power lines is 40cm and they are of a length of 270m each.
The current in the power line is 140A.
The force on each power line due to another can be given by,
F = uI₁I₂L/2πr
Where,
I₁ and I₂ are the current in the line,
L is the length of the wire,
r is the distance between them,
Putting values,
F = 4 x π x 10⁻⁷ x 140 x 140 x 270/2 x π x 0.4
Solving further,
F = 2.646 N.
The force will be away from each other because the current is in same direction. The magnitude of the force will remain same, whatever direction of the current may be.
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