The two light bulbs are to be resolved at a distance of 60.1 km.
The formula of Rayleigh criterion for the diffraction limit is
[tex]\theta \:=\: 1.22 \: \frac{\lambda}{D}[/tex]
where
Because in problems didn't give the detail about the wavelength, for visible light the radiation wavelength is 750 nm - 400 nm. In this problems I assume λ = 600 nm = 600 × 10⁻⁹ m = 6 × 10⁻⁷ m
[tex]\theta \:=\: 1.22 \: \frac{\lambda}{D}[/tex]
θ D = 1.22 λ
θ × 4.00 × 10⁻² = 1.22 × 6 × 10⁻⁷
θ = (7.32 × 10⁻⁷) ÷ (4.00 × 10⁻²)
θ = 1.83 × 10⁻⁵ rad
The angle for the light bulbs
[tex]\theta = \frac{s}{r}[/tex]
where
s = θr
r = 1.1 ÷ (1.83 × 10⁻⁵)
r = 6.01 × 10⁴ m
r = 60.1 km
Learn more about The Rayleigh criterion here: https://brainly.com/question/21881071
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