Consider how the following scenario could be modeled with a binomial distribution, and answer the question that follows. 54.4% of tickets sold to a movie are sold with a popcorn coupon, and 45.6% are not. You want to calculate the probability of selling exactly 6 tickets with popcorn coupons out of 10 total tickets (or 6 successes in 10 trials).

The number of successes in a sample of size n drawn with replacement from a population of size N is typically modeled using the binomial distribution. The mean for this type of distribution is computed by multiplying the number of trials (n) by the probability that they will succeed (p). Then, mean = n×p. The variance is n×p×q, where q is the probability that the event fails. The standard deviation is √(n×p×q).

Here, given that the percentage of tickets sold with popcorn is 54.4% and those not sold is 45.6%, the parameter (p) we used to calculate when the event occurs is 0.544. Because it is the probability that the sale of movie tickets with popcorn occurs.

The answer is 0.544.

The complete question is -

Consider how the following scenario could be modeled with a binomial distribution, and answer the question that follows.

54.4% of tickets sold to a movie are sold with a popcorn coupon, and 45.6% are not.

You want to calculate the probability of selling exactly 6 tickets with popcorn coupons out of 10 total tickets (or 6 successes in 10 trials).

What value should you use for the parameter p?

To know more about binomial distribution:

https://brainly.com/question/14565246

#SPJ4