use newton's method to approximate the zero(s) of the function. continue the iterations until two successive approximations differ by less than 0.001. then find the zero(s) to three decimal places using a graphing utility and compare the results. f(x)

Respuesta :

Only one genuine zero exists, and it is found at x = 1.359. newton's method to approximate the zero(s) of the function

The first three decimal places were repeated in the solution after the fourth iteration. I began by assuming that x = 1 was the answer to the Newton's Method formula.

When I entered 1 for x, I received a zero of 5/3.

I entered 5/3 and repeated the process to get 997/687.

I was able to get 1.36976 by plugging in 997/687 and repeating the process.

I entered 1.36976 and repeated the process to get 1.359454.

I entered 1.359454 and repeated the process to get 1.359304.

There was no need to go any further because we are only interested in accuracy to three decimal places.

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