The equation of the line that passes through the points (-5,1) and (1,3) is x - 3y = -8
From the question, we are to determine the equation of the line that passes through the given points.
The given points are (-5, 1) and (1, 3)
Using the formula,
(y - y₁) / (x - x₁) = (y₂ - y₁) / (x₂ - x₁)
Then,
(y - 1) / (x - (-5)) = (3 - 1) / (1 - (-5))
Simplify
(y - 1) / (x + 5) = 2 / (1 + 5)
(y - 1) / (x + 5) = 2 / 6
(y - 1) / (x + 5) = 1/3
Cross multiply
3(y - 1) = 1(x + 5)
3y - 3 = x + 5
x + 5 = 3y -3
x - 3y = -3 - 5
x - 3y = -8
Hence, the equation is x - 3y = -8
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