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For a science experiment, you would like to use the Doppler effect to double the perceived frequency of a harmonica, from the 261.7-Hz tone (middle C) that it emits, to 523.3 Hz (C_5 note). Which strategy will accomplish your goal more easily: move the observer move the harmonica Calculate the speed the harmonica must have in order for a stationary observer to hear 523.3 Hz. Express your answer to three significant figures and include appropriate units. Calculate the speed an observer must have in order to perceive a 523.3-Hz sound from a stationary harmonica that emits sound at 261.7 Hz. Express your answer to three significant figures and include appropriate units.

Respuesta :

The speed the harmonica must have in order for a stationary observer to hear 523.3 Hz is 171 m/s.

Frequency is the wide variety of occurrences of a repeating event in line with a unit of time. The time period frequency refers to the variety of waves that pass a set factor in unit time. It additionally describes the number of cycles or vibrations undergone for the duration of one unit of time with the aid of a body in periodic motion.

Calculation:-

Velocity of the harmmonica is given by

f = f₀( c/c - Vh)

Vh = - ( 261.7 Hz)(343 m/s)/523.3 Hz - (343 m.s)

   = 161.4 m/s

Therefore the velocity of the harmonica is 171 m/s

Speed of the observer is given by:-

f = f₀( c + v₀ / c)

v₀ = 343 m/s)(523.3 Hz) / (261.7) - (343 m/s

  = 342.8 m/s

Hence the speed of the observer is 343 m/s

Learn more about frequency here:-https://brainly.com/question/254161

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