Respuesta :
It takes [tex]1.815 * 10^{-19}[/tex] Joules of energy for a hydrogen atom to transition an electron from n=3 to n=6.
Energy absorbed by photon (eV)
[tex]E = 13.6 Z^{2} ( \frac{1}{n_{1} ^{2} } -\frac{1}{n_{2} ^{2} } )[/tex]
where Z is the atomic number
[tex]n_{1}[/tex] lower energy state
[tex]n_{2}[/tex] higher energy state
[tex]E =13.6* 1^{2} ( \frac{1}{3 ^{2} } -\frac{1}{6 ^{2} } )\\\\E = 13.6 (\frac{1}{9} -\frac{1}{36} )= \frac{13.6 *3}{36}[/tex]
E = 1.133 eV
To convert energy into J from eV
Multiply it by [tex]1.602 * 10^{-19}[/tex]
E = [tex]1.133 *1.602 * 10^{-19}[/tex]
E = [tex]1.815 * 10^{-19}[/tex] J
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