Respuesta :
The pValue is 0.15625 > 0.05 when brand1 killed all ants in 65 of 100 containers within two hours, and brand 2 killed all ants in 58 of 100 containers within two hours in hypothesis.
Let A represent the new pesticide and B be the Ant Killer. Then, you are given that
Brand1 kills ants in 65 of 100 containers:
Xa = 65/100 = 0.65
Brand2 kills ants in 58 of 100 containers:
Xb = 58/100 = 0.58
You know need to find sample variance for both,
s²A =∑(Xi - Xa)
= 65(1-0.65)² + 35(0 - 0.65)²
= 22.7
s²B =∑(Xi - Xb)²
= 59(1-0.59)² + 41(0 - 0.59)²
= 24.19
You can know do a test for significance
t = (Xa - Xb) / √(sA /nA) +(sB/nB)
and derive the conclusion from there
Here, Null and alternative hypothesis are generally,
Alternative hypothesis
Here, there are three samples are assumed. They are:
i) Samples are taken independently
ii) Samples must be selected randomly
iii) n₁p₁ ≥ 5 , n₁q₁ ≥ 5, n₂p₂ ≥ 5, n₂q₂ ≥ 5
i.e., p₁ = 0.65 ; p₂ = 0.58 , n₁= 100
q₁ = 0.35 ; q₂ = 0.42 , n₂=100
Corresponding p-value at Z = 1.01722
p-value = 0.15625 > 0.05
Hence, the pValue is 0.15625 > 0.05 when brand1 killed all ants in 65 of 100 containers within two hours, and brand 2 killed all ants in 58 of 100 containers within two hours in hypothesis.
To know more about hypothesis check the below link:
https://brainly.com/question/606806
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