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A force of 1.0 x 104 n is exerted on a 50 g bullet throughout the 10 cm length of a gun barrel. how much work was done on the bullet? how much ke did the bullet have when it left the gun barrel? what was the speed of the bullet when it left the gun barrel?

Respuesta :

The kinetic energy of the bullet when it left the gun barrel is 1000J.

We know that ,

K.E. = F d

where, K.E. = kinetic energy

F = force

d = distance

Given, F = 1* 10^4 N

          d = 10cm = 0.1 m

Putting these values in above equation we get,

K.E. = 1000J

So the kinetic energy of the bullet when it left the gun barrel is 1000J.

To know more about kinetics visit:

https://brainly.com/question/15580830

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