The probability that a marksman will hit a target each time he shoots is 0. 89. If he fires 15 times, what is the probability that he hits the target at most 13 times?.

The number of times the target is hit, X, has to be a random variable.
The amount of trials ("n") equals 10 as a result of 15 bullets being fired.
In such a binomial distribution, "p" symbolizes the probability of success and "q" represents the probability of failure (where q = p - 1)
p = 0.89 with q = 0.11 as a result of the 0.89 chance of hitting the target.

For such a binomial distribution, the probability density function equals the amount of successes ("x").

P(X = x) = ⁿCₓ . pˣ . qⁿ⁻ˣ

The required number of achievements is five (i.e., x = 13), as we are keen in the development that the objective will be hit exactly five times.

P(X = 13) = ¹⁵C₁₃. (0.89)¹³ (0.11)²

P(X = 13) = 0.2792

P(X = 13) = 27.92%

Therefore, there is a 27.92% chance that a shooter will hit the target at most 13 times.

To know more about the binomial distribution, here

https://brainly.com/question/23780714

#SPJ4