Nuclear decay occurs according to first-order kinetics. Argon-37 decays with a rate constant of 0. 0198 days–1. After 98. 3 days, a sample has a mass of 2. 14 g. What was the original mass of the sample?.

Respuesta :

The original mass of the Argon-37 sample (N₀) was 14.98651g or approximately 15g. We Use the equation for first-order kinetics for determining the original mass of the given Argon-37 sample.

What is first order rate equation?

If the rate of radioactive decay is first order, we can write r = k[N]1, where N is the quantity of radioisotope present at the time the rate is recorded, k is the isotope's first order rate constant, and r is the rate of decay as observed.

According to First-Order Rate Equation,

[tex]ln(\frac{N}{N_{0} } )=-kt[/tex]

Here,

N = The amount of radioisotope left after "t" time.

N₀= The initial amount of radioisotope,

k = Rate constant of the radioisotope.

t = Time

Given,

N = 2. 14 g.

N₀ = ?

k = 0. 0198

t = 98. 3 days

Now, substituting these values in the first order rate equation we get,

[tex]ln(\frac{N}{N_{0} } )=-kt\\ln(\frac{2.14}{N_{0} } )=-0.0198*98.3\\ln(\frac{2,14}{N_{0} } )=-1.94634\\\frac{2.14}{N_{0} } =e^{-1.94634} \\\frac{2.14}{N_{0} }=0.142795\\N_{0} = 14.98651g[/tex]

Hence, the original mass of the sample (N₀) was 14.98651 g or approximately 15 g.

To know more about radioactive decay please click here, https://brainly.com/question/9932896

#SPJ4