An Endure chosen randomly the likelihood of any battery lasting longer than 550 hours is 10.56%.
These steps are used to determine the Z score:
z = (x - μ)/σ
As mentioned in question-
x > 550 and μ = 500, σ = 40:
z = 550 - 500 / 40
z = 1.25
Obtain the p-value from normal distribution chart,
P(z > 1.25) = 1 - P(z < 1.25)
P(z > 1.25) = 1 - 0.8944
P(z > 1.25) = 0.1056
Thus, an Endure chosen at random the likelihood of any battery lasting longer than 550 hours is 10.56%.
To know more about the z score, here
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