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a 1.5 kg 1.5 kg ball rotates on the end of a 3 m 3 m string in a vertical circle with a speed of 7 m/s 7 m/s. what force does the ball exert on the rope at the top of the vertical circle?

Respuesta :

Force exerted by the ball on the rope is 24.5 N.

Force is an external influence that can change the velocity or motion of an object.

  • It can also be defined as the product of mass and acceleration.
  • Mathematically, force F = m*a

mass of the ball = 1.5 kg

Radius of the circle = 3 m

Speed at which the ball is rotating = 7 m/s

Since the ball is rotating in a vertical circle, centripetal force acts on it.

Centripetal force is the force exerted on a rotating object and the gravitational force in a vertical circle is zero.

Mathematically centripetal force is Fc = mv²/r

Fc = 1.5 * (7)²/ (3)

Fc = 24.5 N

Force exerted by the ball on the rope at the top of the vertical circle is 24.5 N.

To know more about Force,

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