The number of bytes that will be sent or transmitted next is; 1620 bytes
We are given that:
The file size = 100 KB
The payload size = 100 bytes
The negotiated window size = 300 bytes.
This tells us that the sliding window can only accommodate a maximum number of 300/100 = 3 payloads
The sender receives an ACK 1500 from the receiver.
Total byte of the file is :
1000 KB = 1024000 bytes
The TCP header requires 20 bytes and IPV4 header requires 20 bytes.
Total TCP/IP header is composed of 40 bytes.
Sender receives an ACK 1500 from the receiver and as such the overhead which represents the bytes that will be sent next is;
1500 + (3 * 40)
= 1500 + 120
= 1620 bytes
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