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PLEASE HELP!!!!! Need answer immediately

Rania redesigned the bottom of one of the Landing pools. the equation that describes the bottom of the redesigned pool is y = 2/5x -60 in this equation y represents the depth of the water and x is the distance a guest lands away from the far wall all measurements are in inches. How deep is the water in the pool where a guest lands in the water 36 inches from the wall?
A. Y=74.4 in
B. Y=38.4 in
C. Y=45.6 in
D. Y=60 in

Respuesta :

Answer:

B

Step-by-step explanation:

y = 2/5(36) - 60

  = 72/5 - 60

  = 14.4 - 60

  = -38.4

semsee45

Answer:

C. y = 45.6 in

Step-by-step explanation:

Given equation:

[tex]y=\dfrac{2}{5}x-60[/tex]

where:

  • y is the depth of the water (in inches).
  • x is the distance a guest lands away from the far wall (in inches).

If a guest lands 36 inches from the wall, then x = 36.

Substitute x = 36 into the equation:

[tex]\implies y=\dfrac{2}{5}(36)-60[/tex]

[tex]\implies y=\dfrac{2 \cdot 36}{5}-60[/tex]

[tex]\implies y=\dfrac{72}{5}-60[/tex]

[tex]\implies y=14.4-60[/tex]

[tex]\implies y=-45.6[/tex]

Therefore, the depth of the water is 45.6 inches (since -45.6 inches means it is that distance below the surface).

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