if 3.33 mol3.33 mol of an ideal gas has a pressure of 2.11 atm2.11 atm and a volume of 60.51 l,60.51 l, what is the temperature of the sample in degrees celsius?

Respuesta :

The temperature of the sample in degrees celsius is 238.89ºC.

The ideal gas equation can be rewritten to demonstrate that the pressure of a sample of gas is directly proportional to the number of moles of the gas present if volume and temperature are held constant:

deal Gas Law

PV = nRT

P = pressure = 2.10 atm

V = volume = 77.27 L

n = moles = 3.86

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = ?

Solving for T:

T = PV/nR = (2.10)(77.27)/(3.86)(0.0821)

T = 512.04 K

To convert to ºC, subtract 273.15K

T = 512.04 - 273.15 = 238.89ºC

Learn more about the gas constant

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