what is the approximate mole fraction of ethanol, c2h5oh, in an aqueous solution in which the ethanol concentration is 11.0 molal?

Respuesta :

Molecular Mass of Ethanol = 46g

11.0 molal = 11 moles in 1 L solution

Molecular mass of water = 18g

Density of water= 1kg/m3 = 1000g/l

So, Mass of water in 1l solution = 1000g

so moles = 1000/18 = 55.55 moles

Thus, mole fraction of ethanol = 11.0/ ( 11.0 + 55.6 ) = 0.165

What do you mean by mole fraction ?

There are several ways to indicate the concentration of the solution and mole fraction is one of them. Mole fraction is a unit of concentration. In the solution, the relative amount of solute and solvents are measured by the mole fraction and it is represented by “X.”

The mole fraction is the number of moles of a specific component in the solution divided by the total number of moles in the given solution.

To know more about mole fraction from the given link:

https://brainly.com/question/14783710

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