The perimeter of 2nd right isosceles triangle is 16(√2 + 2).
If a is the equal sides of a right isosceles triangle,
Then its hypotenuse is √2 a and perimeter is √2a (√2 + 1 )
The perimeter of 1st right isosceles triangle is 16(√2 + 1)
= √2a (√2 + 1 )
= 16 (√2 + 1 )
a = 8√2
The hypotenuse of 1st triangle = √2 a
= √2 * 8√2
= 16cm
Let A be the equal sides of 2nd right isosceles triangle
Then its hypotenuse is √2 a and perimeter is √2a (√2 + 1 )
According to the question,
A = 16 cm
The perimeter of 2nd right isosceles triangle is √2 * 16(√2 + 1)
= 16(√2 + 2)
Hence, The perimeter of 2nd right isosceles triangle is 16(√2 + 2).
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