2Hbr + sr(oh)₂ --> srbrc + 2h₂0
25ml 16.8 ml
xm 0.105 m
for complete neutralization
Moles of Hbr =2× moles of sr(oh)₂
xm × 25ml = 2 × 16.8 ml × 0.105 m
x = 0.147m
the concentration of the original hbr solution is 0.147m.
How do you make HBr solution?
Distillation of a solution of sodium bromide or potassium bromide with phosphoric acid or sulfuric acid yields HBr: KBr + H2SO4 KHSO4 + HBr Because it oxidises HBr to bromine, concentrated sulfuric acid is less effective: 2 HBr + H2SO4 + 2 H2O Br2 + SO2 + 2 H2O
Hence 0.147m is a correct answer.
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