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gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated naoh(aq).naoh(aq). calculate the amount of ga(s)ga(s) that can be deposited from a ga(iii)ga(iii) solution using a current of 0.390 a0.390 a that flows for 80.0 min.

Respuesta :

The amount of Gallium that can be deposited is 0.450 g.

Obtain the equation of gallium (III) to gallium that occurs in the electrolysis.

Ga³⁺ + 3 e⁻ → Ga

The relations important for the calculations are:

1 minute = 60 second

1 Ampere = 1 Coulomb / second

The charge of 1 mole of electrons is 96,468 Coulomb (Faraday's constant)

1 mole of gallium is deposited when 3 moles of electrons circulate.

The molar mass of gallium = 69.72 g/mol

Obtain the mass of gallium deposited from a Ga(III) solution using a current of 0.390 A that flows for 80.0 min

80 min × 60s/1min × 0.390c/s × 1 mole⁻/96,468c × 1 mol Ga/3 mole⁻ × 69.72g/1mol Ga = 0.450 g

Hence the mass of the Ga deposited is 0.450 g.

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https://brainly.com/question/19866201

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