The dimensions of the photograph are found as 13 in and 6 in.
Let length = x.
So, width = x - 7
Area = length x width
A = x (x -7)
and A = 78 inches squared.
Thus,
78 = x (x -7)
On solving.
x² - 7x - 78 = 0
Find the factors of the quadratic equation,
x² - 7x - 78 = 0
(x - 13)(x + 6) = 0
Thus,
x = 13 and x = -6 but (x > 0)
Thus, when x = 13 in,
Width = x + 7
Width = 13 - 7
Width = 6 in
Thus, the dimensions of the photograph are found as 13 in and 6 in.
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