The table above shows two lists of numbers. Which of the following is a true statement comparing list A and list B ?
A) The means are the same, and the standard deviations are different.
B) The means are the same, and the standard deviations are the same.
C) The means are different, and the standard deviations are different.
D) The means are different, and the standard deviations are the same.

Respuesta :

By using the formula for mean and standard deviation, it can be concluded that

For list A and list B,

The mean are same and the standard deviation are different.

First option is correct

What is mean and standard deviation?

Mean is the average of all the values of a data set.

To know about standard deviation, it is important to know about variance

Variance is the sum of the square of deviation from mean divided by the number of observation

Square root of the variance is the standard deviation.

For list A

Mean = [tex]\frac{1 +2+3+4+5+6}{6}[/tex]

         = 3.5

Variance = [tex]\frac{(1-3.5)^2 + (2 -3.5)^2+ (3 - 3.5)^2 + (4 - 3.5)^2+(5 - 3.5)^2+(6 - 3.5)^2}{6}[/tex]

                = [tex]\frac{6.25 + 2.25 + 0.25 + 0.25 + 2.25 + 6.25}{6}[/tex]

                = 17.5

Standard deviation = [tex]\sqrt{17.5} = 4.18[/tex]

For list B

Mean = [tex]\frac{2 + 3 + 3 + 4 + 4 +5}{6}[/tex]

         = 3.5

Variance = [tex]\frac{(2-3.5)^2 + (3 -3.5)^2+ (3 - 3.5)^2 + (4 - 3.5)^2+(4 - 3.5)^2+(5 - 3.5)^2}{6}[/tex]

               = [tex]\frac{2.25 + 0.25 + 0.25 + 0.25 + 0.25 + 2.25}{6}[/tex]

               = 0.916

Standard deviation = [tex]\sqrt{0.916}[/tex] = 0.957

To learn more about mean and standard deviation, refer to the link-

https://brainly.com/question/26941429

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