The problem has to events, selecting a white bead, and selecting a red bead, without replacement, which means the total number of outcomes changes by one.
[tex]P=\frac{3}{10}\times\frac{5}{9}[/tex]Observe how the number of beads changes to 9 because the first selected is not being replaced.
[tex]P=\frac{3\times5}{10\times9}=\frac{15}{90}=\frac{1}{6}[/tex]